Optimal. Leaf size=341 \[ -\frac{(d+e x)^{7/2} (A b-a B)}{2 b (a+b x) \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}-\frac{(d+e x)^{5/2} (-7 a B e+3 A b e+4 b B d)}{4 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}-\frac{5 e (a+b x) \sqrt{b d-a e} (-7 a B e+3 A b e+4 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 b^{9/2} \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e (a+b x) \sqrt{d+e x} (-7 a B e+3 A b e+4 b B d)}{4 b^4 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e (a+b x) (d+e x)^{3/2} (-7 a B e+3 A b e+4 b B d)}{12 b^3 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)} \]
[Out]
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Rubi [A] time = 0.724562, antiderivative size = 341, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.171 \[ -\frac{(d+e x)^{7/2} (A b-a B)}{2 b (a+b x) \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}-\frac{(d+e x)^{5/2} (-7 a B e+3 A b e+4 b B d)}{4 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}-\frac{5 e (a+b x) \sqrt{b d-a e} (-7 a B e+3 A b e+4 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 b^{9/2} \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e (a+b x) \sqrt{d+e x} (-7 a B e+3 A b e+4 b B d)}{4 b^4 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e (a+b x) (d+e x)^{3/2} (-7 a B e+3 A b e+4 b B d)}{12 b^3 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)} \]
Antiderivative was successfully verified.
[In] Int[((A + B*x)*(d + e*x)^(5/2))/(a^2 + 2*a*b*x + b^2*x^2)^(3/2),x]
[Out]
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Rubi in Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: RecursionError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(e*x+d)**(5/2)/(b**2*x**2+2*a*b*x+a**2)**(3/2),x)
[Out]
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Mathematica [A] time = 0.789502, size = 191, normalized size = 0.56 \[ \frac{(a+b x)^3 \left (\frac{\sqrt{d+e x} \left (-\frac{3 (b d-a e) (-13 a B e+9 A b e+4 b B d)}{a+b x}-\frac{6 (A b-a B) (b d-a e)^2}{(a+b x)^2}+8 e (-9 a B e+3 A b e+7 b B d)+8 b B e^2 x\right )}{3 b^4}-\frac{5 e \sqrt{b d-a e} (-7 a B e+3 A b e+4 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{9/2}}\right )}{4 \left ((a+b x)^2\right )^{3/2}} \]
Antiderivative was successfully verified.
[In] Integrate[((A + B*x)*(d + e*x)^(5/2))/(a^2 + 2*a*b*x + b^2*x^2)^(3/2),x]
[Out]
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Maple [B] time = 0.036, size = 1150, normalized size = 3.4 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(e*x+d)^(5/2)/(b^2*x^2+2*a*b*x+a^2)^(3/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(e*x + d)^(5/2)/(b^2*x^2 + 2*a*b*x + a^2)^(3/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.29341, size = 1, normalized size = 0. \[ \left [-\frac{15 \,{\left (4 \, B a^{2} b d e -{\left (7 \, B a^{3} - 3 \, A a^{2} b\right )} e^{2} +{\left (4 \, B b^{3} d e -{\left (7 \, B a b^{2} - 3 \, A b^{3}\right )} e^{2}\right )} x^{2} + 2 \,{\left (4 \, B a b^{2} d e -{\left (7 \, B a^{2} b - 3 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{\frac{b d - a e}{b}} \log \left (\frac{b e x + 2 \, b d - a e + 2 \, \sqrt{e x + d} b \sqrt{\frac{b d - a e}{b}}}{b x + a}\right ) - 2 \,{\left (8 \, B b^{3} e^{2} x^{3} - 6 \,{\left (B a b^{2} + A b^{3}\right )} d^{2} + 5 \,{\left (19 \, B a^{2} b - 3 \, A a b^{2}\right )} d e - 15 \,{\left (7 \, B a^{3} - 3 \, A a^{2} b\right )} e^{2} + 8 \,{\left (7 \, B b^{3} d e -{\left (7 \, B a b^{2} - 3 \, A b^{3}\right )} e^{2}\right )} x^{2} -{\left (12 \, B b^{3} d^{2} -{\left (163 \, B a b^{2} - 27 \, A b^{3}\right )} d e + 25 \,{\left (7 \, B a^{2} b - 3 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{e x + d}}{24 \,{\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}}, -\frac{15 \,{\left (4 \, B a^{2} b d e -{\left (7 \, B a^{3} - 3 \, A a^{2} b\right )} e^{2} +{\left (4 \, B b^{3} d e -{\left (7 \, B a b^{2} - 3 \, A b^{3}\right )} e^{2}\right )} x^{2} + 2 \,{\left (4 \, B a b^{2} d e -{\left (7 \, B a^{2} b - 3 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{-\frac{b d - a e}{b}} \arctan \left (\frac{\sqrt{e x + d}}{\sqrt{-\frac{b d - a e}{b}}}\right ) -{\left (8 \, B b^{3} e^{2} x^{3} - 6 \,{\left (B a b^{2} + A b^{3}\right )} d^{2} + 5 \,{\left (19 \, B a^{2} b - 3 \, A a b^{2}\right )} d e - 15 \,{\left (7 \, B a^{3} - 3 \, A a^{2} b\right )} e^{2} + 8 \,{\left (7 \, B b^{3} d e -{\left (7 \, B a b^{2} - 3 \, A b^{3}\right )} e^{2}\right )} x^{2} -{\left (12 \, B b^{3} d^{2} -{\left (163 \, B a b^{2} - 27 \, A b^{3}\right )} d e + 25 \,{\left (7 \, B a^{2} b - 3 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{e x + d}}{12 \,{\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(e*x + d)^(5/2)/(b^2*x^2 + 2*a*b*x + a^2)^(3/2),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(e*x+d)**(5/2)/(b**2*x**2+2*a*b*x+a**2)**(3/2),x)
[Out]
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GIAC/XCAS [A] time = 0.322811, size = 649, normalized size = 1.9 \[ -\frac{5 \,{\left (4 \, B b^{2} d^{2} e^{2} - 11 \, B a b d e^{3} + 3 \, A b^{2} d e^{3} + 7 \, B a^{2} e^{4} - 3 \, A a b e^{4}\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right ) e^{\left (-1\right )}}{4 \, \sqrt{-b^{2} d + a b e} b^{4}{\rm sign}\left (-{\left (x e + d\right )} b e + b d e - a e^{2}\right )} + \frac{{\left (4 \,{\left (x e + d\right )}^{\frac{3}{2}} B b^{3} d^{2} e^{2} - 4 \, \sqrt{x e + d} B b^{3} d^{3} e^{2} - 17 \,{\left (x e + d\right )}^{\frac{3}{2}} B a b^{2} d e^{3} + 9 \,{\left (x e + d\right )}^{\frac{3}{2}} A b^{3} d e^{3} + 19 \, \sqrt{x e + d} B a b^{2} d^{2} e^{3} - 7 \, \sqrt{x e + d} A b^{3} d^{2} e^{3} + 13 \,{\left (x e + d\right )}^{\frac{3}{2}} B a^{2} b e^{4} - 9 \,{\left (x e + d\right )}^{\frac{3}{2}} A a b^{2} e^{4} - 26 \, \sqrt{x e + d} B a^{2} b d e^{4} + 14 \, \sqrt{x e + d} A a b^{2} d e^{4} + 11 \, \sqrt{x e + d} B a^{3} e^{5} - 7 \, \sqrt{x e + d} A a^{2} b e^{5}\right )} e^{\left (-1\right )}}{4 \,{\left ({\left (x e + d\right )} b - b d + a e\right )}^{2} b^{4}{\rm sign}\left (-{\left (x e + d\right )} b e + b d e - a e^{2}\right )} - \frac{2 \,{\left ({\left (x e + d\right )}^{\frac{3}{2}} B b^{6} e^{4} + 6 \, \sqrt{x e + d} B b^{6} d e^{4} - 9 \, \sqrt{x e + d} B a b^{5} e^{5} + 3 \, \sqrt{x e + d} A b^{6} e^{5}\right )} e^{\left (-3\right )}}{3 \, b^{9}{\rm sign}\left (-{\left (x e + d\right )} b e + b d e - a e^{2}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(e*x + d)^(5/2)/(b^2*x^2 + 2*a*b*x + a^2)^(3/2),x, algorithm="giac")
[Out]